I hope it helps in your albino project!
I'll attempt a chart below which may help in understanding the sex linked albino as I understand it. I'm human and do make mistakes though haha.
Albino male x non albino female = 100% albino female, 100% non albino male split or carrying albino.
Using the chicks above..
Albino female x non albino male = 100% non albino females, 100% non albino males split to or carrying the albino gene.
NON albino male(carrying or split to albino) x non albino female = 50%(25%) female chicks are albino, 50% female chicks are non albino, 50%(25%) male chicks carry or are split for albino and 50%(25%) male non albino carriers.
The 25%'s are over all clutch sizes. so if you had 4 chicks, 1/4 is 25% on average. This also assumes a 50/50 split on male to female ratio's.
Taking a male who carries albino(he will show a normal color but carry this albino gene) and breeding to a albino hen is the best way to get a high percentage of albino chicks of both sexes with less abnormalities if they prove to have them.
Male non albino (split or carrying albino) x Albino hen = 50%(25%) albino female chicks, 50%(25%)non albino female chicks. 50%(25%) Albino male, 50%(25%) non albino male who carries or is split to albino.
Albino x albino is 100% of all chicks of both sexes being albino as you know. This pairing could tell you what abnormalities to expect and how over all weak this gene causes chicks to be. I'd expect high mortality, birth defects, early death in shell or even failure to develop.
So using that info, any chick Bino has that is albino is most likely a female unless it's mother is albino. All of Bino's boy chicks will look like normal dark eyed chicks but carry the albino gene and will pass it to 50% of their daughters.
The father (xx) gives one of his X's to the girl offspring and since he's albino on both X's, the girl IS albino (she receives the Y from her mother and it's not a color gene).
The father gives one of his X genes to his son. This X gene will be albino since that's all the father has. if the son gets a normal X from his mother he's a normal color but carries albino on the other X he got from dad. If his father gives him a albino X gene and his mother gives him the 2nd albino X gene, the son is albino.
the mother(xy) gives her X, think of this gene as the one which shows mother's color, she gives this X to her son. So if mom is albino her son will have albino on one of his X's. This means he will hide that color if the color of his other X received from dad is dominate like a normal color.
The mother will give her Y gene to her daughters. It has no bearing on daughter's color. Only the father's X gene will determine daughter color.
Don't disregard your dark eyed chicks from Bino's first hatch. They are most likely boys who carry that albino and will produce a lot of hens who are albino! :D I would use Bino's sons to albino hens. That gives you the highest safe percentage of albino chicks in both sexes.
If this albino gene is not sex linked my little biology lesson is useless. BUT albino is a sex linked gene in other birds.
This also gives you a easy way of adding new blood or diluting without loosing the albino gene. You can add a unrelated hen to Bino. this makes 100% albino females and 100% male normal color (albino carriers) who are only 1/2 related to your current bloodlines. This can dilute your blood lines so less recessive abnormalities show up. It is also a way to get the albino into different chicken breeds although some inbreeding will have to be done to get back to the standard of a different chicken type.
Edited by yellowherb - 3/17/16 at 1:55am