First time experiencing chicken math

Discussion in 'Managing Your Flock' started by andreanar, Oct 14, 2017.

  1. andreanar

    andreanar Crowing

    2,493
    3,668
    397
    May 16, 2014
    Upstate NY
    Had 10 chooks. 1 was a cockerel, so leaves me with 9 pullets. So I had to replace him, right? So, I pick out 2 new chicks, but that would leave the 3rd one all alone, so I take all 3. 3 chicks=1 cockerel. But, I'm thinking, none of my 27 week old pullets are laying, so its not like they count as whole chickens! So, there is no reason that I cant go to the chicken sale coming up. 2 pullets=1 hen. 3 chicks=1 hen. So I really only have 5 1/2 chickens.
    I think that's how it adds up.
     
  2. 21hens-incharge

    21hens-incharge Enabler

    9,863
    26,169
    1,132
    Mar 9, 2014
    Northern Colorado
    :hmm

    If none are laying I think you actually have 0.

    Now if any are bantams that drops you into the negatives. Negatives create a vortex that draws chickens to fill the negative space.
    :oops:

    I think you have to do something soon lest the neighborhood be over run with chickens drawn to your very empty coop! :lau
     
  3. eatbeef14

    eatbeef14 Chirping

    78
    84
    77
    Dec 24, 2016
    Love it. I think I only have 2 chickens I better go buy 18. :lau
     
  4. rebrascora

    rebrascora Crowing

    6,076
    6,330
    496
    Feb 14, 2014
    Consett Co.Durham. UK
    You are clearly into advanced Mathematics! Whilst I've experimented with addition and multiplication and sadly some subtraction, I hadn't considered chicken algebra..... ie 2p=1h and 3c=1h so 9p+3c=5.5h....Wow!
    Hope you have plenty of space! From experience, chicken maths is great until it suddenly gets out of hand, particularly going into winter.
     
  5. lulu_lulu

    lulu_lulu In the Brooder

    17
    16
    39
    Oct 10, 2017
    What this chiken math about??
    Are u gonna trade 3 chick for 1 hen or something??
     
  6. ocap

    ocap Crowing

    4,555
    616
    291
    Jan 1, 2013
    Smithville, Missouri
    be careful about over crowding ... an acre is 209 feet by 209 feet ... each hen requires 10 square feet so multiply 209 by 209 and divide by 10= 436 hens per acre without building a second story :D
     
  7. hlhutchinson

    hlhutchinson Songster

    642
    651
    201
    Aug 26, 2015
    Casper Wyo
    :yuckyuck
     
  8. hlhutchinson

    hlhutchinson Songster

    642
    651
    201
    Aug 26, 2015
    Casper Wyo
    Yep math looks good to me
     
  9. asher

    asher Chicken Enabler Extraordinaire

    3,446
    17
    244
    Jan 26, 2007
    Mountains of NC
    I never used to count because then I never had to admit how many I actually had if someone asked. ;-)
     
  10. shartnett5

    shartnett5 Songster

    96
    112
    112
    Apr 16, 2017
    Southern New Hampshire
    :woot
     
    Anansi, biophiliac and andreanar like this.

BackYard Chickens is proudly sponsored by: