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Discussion in 'Raising Baby Chicks' started by Bentley13, Sep 23, 2015.
What rooster and hen do I need to get a Blue Laced Wyandotte? And, for a Jubilee Orpington?
To my knowledge, I do not think you can cross chickens of different breeds/varieties and get the breeds you listed. You simply need to breed a Blue Laced Wyandotte hen and rooster to get them. If you have further questions, I would recommend posting in the apt section: "Exhibition, Genetics, & Breeding to the Standard of Perfection."
Have a great day!
Thank you Ill check it out. I hope that's all there is to it but I think they are made by a black crossed with a splashed Wyandotte. Not sure though. I don't yet understand all the genetics and chromosomes yet lol Way over my head right now.
You can't create those colors by simply crossing two breeds and/or varieties. If you are in the US blue laced red Wyandottes should be relatively easy to find. Be aware that blue does NOT breed true, so you will get black laced red and splash laced red in the mix.
I am less familiar with the jubilee coloring, though some are available in the US also.
black laced red x black laced red = 100% black laced red
black laced red x blue laced red = 50% black laced red, 50% blue laced red
black laced red x splash laced red = 100% blue laced red
blue laced red x blue laced red = 25% black laced red, 50% blue laced red, 25% splash laced red
blue laced red x splash laced red = 50% blue laced red, 50% splash laced red
splash laced red x splash laced red = 100% splash laced red (over time the splashing will wash out)
You would need a rooster and hen of each color variety and breed. If you want to breed pure Blue Laced Red Wyandottes, then get Blue Laced Red Wyandottes. If you want Jubilee Orpingtons, get Jubilee Orpingtons. You can't start crossing in different breeds and color varieties and expect to get something that meets breed standard. It took many years, and lots of careful breeding and culling to develop those particular color varieties and maintain the breed standard.
The way the blue dilute gene works is that it dilutes all the black on a bird. A single copy of the gene changes black to blue. A double copy is what is called splash, it changes black to white or light grey. Black birds have no dilute gene.
The 'jubilee' gene is the same gene as speckled. It's recessive. Both parents require at least one copy to produce chicks with the speckled gene.
So I need a black x splash to equal a blue (as stated in another comment) or just 2 blues to create a blue?
I posted the possibilities in an earlier post.
The color blue can vary from a pale color to a dark, almost black. It depends on what other melanisers are present.
Black to splash is the only way to ensure that all chicks will be blue.