Search results for query: *

Yes, as stated above: silkie x bowtie sg = 50% silkie, 50% bowtie sg silkie x no bowtie sg = 100% bowtie sg

Yes, that's correct. silkie x bowtie sg = 50% silkie, 50% bowtie sg bowtie sg x bowtie sg = 25% silkie, 50% bowtie sg, 25% no bowtie sg bowtie sg x no bowtie sg = 50% bowtie sg, 50% non bowtie sg silkie x no bowtie sg = 100% bowtie sg

Yes, one copy of the gene gives a bowtie, two copies and there's no bowtie. If you breed the one with no bowtie to a non, nn bird, you'll get 100% with a bowtie.