Anyone Here Good at Math? - Math and Medications

Exercise Number Two


What the above picture says is that the dose should be 20 mg of amprolium per 1kg (kilogram) of bird weight.

Calculate doses for the following:
  • 2 ounce chick
  • 7 ounce chick
  • 1 pound bird
  • 10 pound bird

Show your work!

-Kathy

More conversions needed to get from ounces and pounds to mg/g/kg:

1 kilogram (kg) = 1000 grams (g) = 1000000 milligrams (mg) ( multiply kilograms by 1,000 to get grams or multiply 1,000,000 to get milligrams)
1 ounce (oz) = 28349.52 mg or 28.34952 g or 0.02835 kg (divide 28349.52 milligrams by 1,000 to get grams or divide by 1,000,000 to get kilograms)
1 pound (lb) = 16 oz

Lets first calculate bird weight in kilograms using the formulas above:

2 ounce chick = 0.02835 kg x 2 oz = 0.056 kg
7 ounce chick = 0.02835 kg x 200 oz = 0.19845 kg
1 pound bird (1 lb is 16 oz) = 0.02835 kg x 16 oz = 0.4536 kg
10 pound bird (10 lb x 16 oz = 160 oz) = 0.02835 kg x 160 oz = 4.536 kg

Now for the amprolium at 20 mg per kilogram of bird. Easy... now you just multiply 20 times the bird weight in kilograms:

2 ounce chick = 20mg x 0.056 kg = 1.12 mg of amprolium
7 ounce chick = 20mg x 0.19845 kg = 3.969 mg of amprolium
1 pound bird = 20mg x .4536 kg = 9.072 mg of amprolium
10 pound bird = 20mg x 4.536 kg = 90.72 mg of amprolium
 
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So how many ml's for each?

-Kathy

Measuring 9.6% amprolium in mg = 0.096 mg x 1000 = 96g which is equal to 96ml (equal density 1 to 1 water mass/volume weight conversion). then the amount of amprolium in each dose in milliliters is...

2 ounce chick = dose of 1.12 mg of amprolium = 1.12mg divided by 96g = 0.011667g or 0.012ml
7 ounce chick = 3.969 mg dose of amprolium = 113.4 mg divided 96g = 0.041344g or 0.04ml
1 pound bird = 9.072 mg of amprolium = 9.072 mg divided by 96g = 0.0945g or 0.095ml
10 pound bird = 90.72 mg of amprolium 90.72 mg divided by 96g = 0.945g or 0.95ml


Ok figured out where I went wrong the first time and corrected it
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Exercise Number Two

Second up is how to calculate an oral drench of 9.6% amprolium based on this:

Source: http://www.manorvets.co.uk/ckfinder/userfiles/files/Manor chickens.pdf

What the above picture says is that the dose should be 20 mg of amprolium per 1kg (kilogram) of bird weight.

Calculate doses for the following:
  • 2 ounce chick
  • 7 ounce chick
  • 1 pound bird
  • 10 pound bird

Show your work!

-Kathy

Edited to change 200 ounce to 7 ounce

Edited by casportpony - Today at 12:51 pm
The formula I use is weight of bird in kg, times number of mg per kg, divide by number of mg per ml = number of ml to give.

2 ounces is 56.6990463 grams, so I round up to 57 grams. 57 grams is 0.057 kg, the liquid has 96 mg amprolium per ml, so it's
0.057 x 20 ÷ 96 = 0.011875 ml and I round up to 0.12 ml.

7 ounces is 198.447 grams, so I round up to 200 grams. 200 grams is 0.2kg.
0.2 x 20 ÷ 96 = 0.04166666666 ml - round up to 0.042 ml

For pounds I divide the pound by 2.2 to convert to kg.
1 pound bird - 1
÷ 2.2 x 20 ÷ 96 = 0.09469696969 - round up to 0.095 ml
10 pound bird - 10
÷ 2.2 x 20 ÷ 96 = 0.94696969697 - round up to 0.95 ml

-Kathy
 
Note that I made a big typo... I meant to have a 7 ounce chick, not a 200 ounce chick, lol.

-Kathy

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Exercise Number Three


How many milligrams (mg) of amprolium are there in:
  • One gallon at the 0.024% level = ??? mg
  • One gallon at the 0.012% level = ??? mg
  • One gallon at the 0.006% level = ??? mg


-Kathy

Using these formulas to convert from ounces to milliliters to grams for each of the 3 solutions:
1oz = 29.5735ml = 29.5735g
16oz = 473.176ml = 473.176g
8oz = 236.588ml = 236.588g
4oz = 118.294ml = 118.294g

0.024%: 16oz amp/50 gal = 473.176g divided by 50gal = 9.46352g per gallon
0.012%: 8oz amp/50 gal = 236.588g divided by 50gal = 4.73176g per gallon
0.006%: 4oz amp/50 gal = 118.294g divided by 50gal = 2.36588g per gallon

Next convert g/gal back to milligrams by multiplying by 1000 (shown in to formulas below).

Then find out how much amprolium there is in each gallon of solution. Convert the 9.6% amprolium into a decimal by moving two decimal places to the left (0.096). Then multiply by the amount in milligrams of each solution.

0.024%: 9463.52mg x 0.096 = 908.49792 mg amprolium in one gallon
0.012%: 4731.76mg x 0.096 = 454.24896 mg amprolium in one gallon
0.006%: 2365.88mg x 0.096 = 227.12448 mg amprolium in one gallon

Should be correct this time
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Sorry if I wasn't clear... looking for the number of "mg of amprolium" associated with each dose.
Hint - 1 ml or the liquid has 96 mg, 2 ml have 192 mg, 3 have 288 mg.

-Kathy
 
Sorry if I wasn't clear... looking for the number of "mg of amprolium" associated with each dose.
Hint - 1 ml or the liquid has 96 mg, 2 ml have 192 mg, 3 have 288 mg.

-Kathy

My brain is getting dizzy. I got to run to the feed store so I'll try again when I return. Maybe another member could give it a whirl before I get back.
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