Please, for blue use Bl. B is barring.
Blue is a gene that dilutes black pigment. It is an autosomal (not sex-linked) incompletely dominant gene. Incompletely dominant means that a bird with one copy versus two copies of the allele will display an intermediate result of the trait: blbl = off, Blbl = partially on, BlBl = completely on
For example, frizzle is another incompletely dominant gene. One copy curls the birds feathers noticeably, whereas two copies curls the feathers so much that they become brittle and break easily.
Back to blue--two copies of the not-blue allele, bl, and the black pigment is not diluted at all, at least not by the blue gene. One copy of the Bl allele and one of bl dilutes black pigment to a shade of bluish grey; two copies of Bl further dilutes the pigment to a lighter background shade with irregular, random splashes of darker pigment. A bird who is blbl is black--all black pigment in the bird is undiluted; a bird who is Blbl is blue, and one who is BlBl is splash.
For an analogy, if you were to take a pair of black pants and run them through the washer with a cupful of bleach, they would be lighter in shade when you finished the wash load. Okay, let's imaging that rather than putting them into the dryer you added more bleach to them, letting them sit wrinkled and soaking--essentially tie-dying them with bleach. The resulting pants would be lighter with irregular dark areas.
All birds have two copies of each gene (for this discussion we're ignoring the sex-linked genes, where this statement does not hold true for females).
When two birds breed and create a fertile egg, the egg receives one copy of each gene from each parent. If the parent is BlBl, he or she can only pass on that allele--all the offspring will receive Bl from the parent. The same thing holds true with a parent who is blbl. Carrying two copies of the same allele is called homozygous.
However, when a parent is Blbl, sometimes the parent will give Bl to offspring and sometimes bl. There is a 50% chance for each, which translates into about half the offspring receiving the Bl allele and the other half receiving the bl allele. When the two alleles carried are not the same, it is heterozygous.
At this point we can make a table to show the resulting percentages for the blue gene with the of pairing any two birds.
SplashXSplash
Bl Bl
Bl BlBl BlBl
Bl BlBl BlBl
BlackXBlack
bl bl
bl blbl blbl
bl blbl blbl
If parent A & parent B are both Bl, then all offspring will receive Bl from each parent, giving them the genotype of BlBl: splash. Likewise, if both parents are blbl, all offspring will be blbl: black.
SplashXBlack
bl bl
Bl Blbl Blbl
Bl Blbl Blbl
If parent A is BlBl and parent B is blbl, then all offspring will be Blbl, having receive Bl from parent A and bl from parent B. They will be blue.
SplashXBlue
Bl bl
Bl BlBl Blbl
Bl BlBl Blbl
If parent A is BlBl and parent B is Blbl, then they will always receive a copy of Bl from parent A. Half will receive a 2nd copy of Bl from parent B and the other half will receive bl from parent B. Half will be BlBl and half will be Blbl.
BlackXBlue
Bl bl
bl blBl blbl
bl blBl blbl
Essentially the same thing occurs if parent A is blbl and parent B is Blbl--it is just that instead of all receiving a copy of Bl from parent A, they receive bl. Half will be blbl & half will be blBl. Since the dominant gene is always listed first, Blbl.
BlueXBlue
Bl bl
Bl BlBl Blbl
bl Blbl blbl
When both parents are heterozygous, Blbl, it is slightly more complicated. Half will receive Bl from parent A, and half of those will also receive Bl from parent B, the other half of the one who received Bl from parent A will receive bl from parent B. Likewise, of the half who receive bl from parent A, half will receive Bl and the other half bl from parent B. Add those up and 50% will be homozygous--split equally between BlBl & blbl (25% each). The other half will be heterozygous.
Blue is a gene that dilutes black pigment. It is an autosomal (not sex-linked) incompletely dominant gene. Incompletely dominant means that a bird with one copy versus two copies of the allele will display an intermediate result of the trait: blbl = off, Blbl = partially on, BlBl = completely on
For example, frizzle is another incompletely dominant gene. One copy curls the birds feathers noticeably, whereas two copies curls the feathers so much that they become brittle and break easily.
Back to blue--two copies of the not-blue allele, bl, and the black pigment is not diluted at all, at least not by the blue gene. One copy of the Bl allele and one of bl dilutes black pigment to a shade of bluish grey; two copies of Bl further dilutes the pigment to a lighter background shade with irregular, random splashes of darker pigment. A bird who is blbl is black--all black pigment in the bird is undiluted; a bird who is Blbl is blue, and one who is BlBl is splash.
For an analogy, if you were to take a pair of black pants and run them through the washer with a cupful of bleach, they would be lighter in shade when you finished the wash load. Okay, let's imaging that rather than putting them into the dryer you added more bleach to them, letting them sit wrinkled and soaking--essentially tie-dying them with bleach. The resulting pants would be lighter with irregular dark areas.
All birds have two copies of each gene (for this discussion we're ignoring the sex-linked genes, where this statement does not hold true for females).
When two birds breed and create a fertile egg, the egg receives one copy of each gene from each parent. If the parent is BlBl, he or she can only pass on that allele--all the offspring will receive Bl from the parent. The same thing holds true with a parent who is blbl. Carrying two copies of the same allele is called homozygous.
However, when a parent is Blbl, sometimes the parent will give Bl to offspring and sometimes bl. There is a 50% chance for each, which translates into about half the offspring receiving the Bl allele and the other half receiving the bl allele. When the two alleles carried are not the same, it is heterozygous.
At this point we can make a table to show the resulting percentages for the blue gene with the of pairing any two birds.
SplashXSplash
Bl Bl
Bl BlBl BlBl
Bl BlBl BlBl
BlackXBlack
bl bl
bl blbl blbl
bl blbl blbl
If parent A & parent B are both Bl, then all offspring will receive Bl from each parent, giving them the genotype of BlBl: splash. Likewise, if both parents are blbl, all offspring will be blbl: black.
SplashXBlack
bl bl
Bl Blbl Blbl
Bl Blbl Blbl
If parent A is BlBl and parent B is blbl, then all offspring will be Blbl, having receive Bl from parent A and bl from parent B. They will be blue.
SplashXBlue
Bl bl
Bl BlBl Blbl
Bl BlBl Blbl
If parent A is BlBl and parent B is Blbl, then they will always receive a copy of Bl from parent A. Half will receive a 2nd copy of Bl from parent B and the other half will receive bl from parent B. Half will be BlBl and half will be Blbl.
BlackXBlue
Bl bl
bl blBl blbl
bl blBl blbl
Essentially the same thing occurs if parent A is blbl and parent B is Blbl--it is just that instead of all receiving a copy of Bl from parent A, they receive bl. Half will be blbl & half will be blBl. Since the dominant gene is always listed first, Blbl.
BlueXBlue
Bl bl
Bl BlBl Blbl
bl Blbl blbl
When both parents are heterozygous, Blbl, it is slightly more complicated. Half will receive Bl from parent A, and half of those will also receive Bl from parent B, the other half of the one who received Bl from parent A will receive bl from parent B. Likewise, of the half who receive bl from parent A, half will receive Bl and the other half bl from parent B. Add those up and 50% will be homozygous--split equally between BlBl & blbl (25% each). The other half will be heterozygous.