All those letters confuse me as well. My history is with parrots, so I get which genes are recessive, which are sex linked, etc.... But I have NO CLUE when it comes to alleles, loci, and so forth. I just know "what to what equals what". And the fact that parrot sex linked genes involve the male and not the female (as in chickens) really threw me for a loop!
If you think of it as "colors" and "patterns" this genetic thing becomes a bit easier if you don't understand all the letters.
Mille Fleur is a pattern, and the pattern is pied/mottled.
Lavender is not quite a color - its a color DILUTER. It doesn't add color, it takes it away.
Add the lavender gene to the mille fleur pattern, and you have porcelain. The gold background color in mille fleur dilutes to become straw colored, and the black dilutes to become lavender colored.
Lavender doesn't affect white. White is not technically a color either - its a color "blocker" or "cover upper". Where there is blocked color or covered up color, it cannot be visually diluted.
Now, in the parrot world, we have "visuals" and "splits". Visuals are just that - they are "visual" for that color, meaning you can SEE it. Splits CARRY a color, and you cannot see it.
As for the mode of inheritance, lavender and pied/mottled are both "recessive" genes. Recessive genes must come from BOTH parents to become visual in the chicks. If it only comes from one parent, the chicks will inherit one copy from the visual parent and will be a carrier (aka be "split to" it). And recessive genes have nothing to do with the sexes of the parents.
So, if you breed a visual mille fleur to a visual mille fleur, one pied/mottled gene comes from mom, one comes from dad, and the chicks inherit both of them and will be visual mille fleur. Same thing with lavender - lavender x lavender = lavender.
But lavender (color diluter) and mille fleur (pattern) are two separate entities. One does not equal the other and they are totally unrelated.
So it stands to reason that when one parent is a mille fleur and one parent is a lavender, the chicks will inherit one lavender gene from the lavender parent, and one pied/mottled gene from the mille fleur parent. They need two copies of EACH of these genes to be visual. And since they only inherited one copy of each, they will be carriers of each (aka "split to" each) - and without TWO copies of EACH of those genes, their color will revert to black. SO.... Mille fleur x lavender = black split to pied/mottled AND lavender.
On the other hand, if a mille fleur (pied/mottled pattern only) is bred to a porcelain (pied/mottled pattern AND dilute color) the chicks will inherit one pied/mottled gene from one parent, and the pied/mottled gene AND the dilute gene (lavender) from the other. So they will get TWO pied/mottled genes and ONE dilute or lavender gene - there by making them visual mille fleur split to lavender.
But since a porcelain is a visual lavender mille fleur (it has the visually diluted color AND the visually pied/mottled pattern), and a lavender only has the diluted color (and NOT the pattern), you cannot expect anything but lavenders if you breed them together. One parent contributes a lavender gene, and one parent contributes a lavender gene AND a pied/mottled gene, therefore the chicks will inherit TWO lavender genes (visual) and ONE pied/mottled gene (split). In other words, the chicks will be lavender split to pied/mottled.
If wegotchickens got a black chick from a lavender x porcelain breeding, then something is wrong. One of the parents is not a visual lavender or visual pied/mottled.
Jeeze, my head is spinning - hope y'all's aren't...