Quote:
should have added... 13 years ago, smith was 39 and jones 26
duh... didn't see someone already posted the answer while I was calculating...
It's ok, I did it wrong so everyone could see.
You try doing math on two different cold medications.
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But you can't pick a random time for Smith to be twice as old as Jones, it must be at the same point that Jones is currently = Smith age.
Given that Jone's current age is X
When Smith age = twice jones age, smith's age = x
I said that kinda odd:
Hummm-
It's like this:
When I was...
Quote:
But you can't pick a random time for Smith to be twice as old as Jones, it must be at the same point that Jones is currently = Smith age.
Given that Jone's current age is X
When Smith age = twice jones age, smith's age = x
Quote:
wait, lets see- but there Smith was never twice Jone's age...
53 & 38
52 & 37
51 & 36
50 & 35
49 & 34
...
38 & 15 <---- where smith is the same age you say Jones is now...
Ok, let me try on the net book.
I have a kid his age is X
I have a cousin's kid who is " (now) twice as old as my kid when she (the cousin's kid) was the age my child is"
The combined age is 8.
X = my kids age now
2x+x = twice my kids current age plus my kids age= cosin's kids current age =...
Where X is jones age now and 2x+x is smith age now
(Where smith has aged x years from when he was twice jones age) so x+x+2x+x = 91
So 4x = 91. Solve for x, then solve for smith age.
EDIT for typos