Is black always black?

[gunslinger33]

This might be a dumb question but I am curious if black is always dominant relative to the colors used to create black.

If I used a Isabel Cuckoo over a silver penciled and the chick is black and that chick is bred back to either color will the black still dominate the doubling up of the other colors?

 

[nicalandia]

This might be a dumb question but I am curious if black is always dominant relative to the colors used to create black.

If I used a Isabel Cuckoo over a silver penciled and the chick is black and that chick is bred back to either color will the black still dominate the doubling up of the other colors?

Extended Black is the most dominant of the e allele mutations, in this case Isabel Cuckoo are based on dominant black(E/E), Silver Penciled is based on one of the most recessive of the e allele which is eb brown. in this case the cross will be E/eb with black chick down(due to lavender being recessive also lavender is lav/lav, so the F1 cross will be Lav+/lav) If the E/eb, Lav+/lav chick(which will be mostly black) is crossed back to Silver Penciled the Progeny will have 50% chance of being eb/eb and 50% E/eb, at that time you will not know which one will cary lavender hidden(50% will be Lav/lav+). Also you need to take into account the sex linked barring gene. if the Lavender Cuckoo are homozygous for Cuckoo then the F1 hens and F1 roosters will be dark Cuckoo(Males will be B/b+, females will be B/-)

 

[gunslinger33]

The chick is about 6 weeks with some light areas around it’s throat and a couple of wing patches

There is a chance the rooster could have been Chocolate Cuckoo , another diluted black

So if I went back to a barred variety the males would be barred and females solid ?

Thank you for responding.

 

[NatJ]

So if I went back to a barred variety the males would be barred and females solid ?

If the rooster is not barred and the hens are barred, yes.

 

[gunslinger33]

Both of my Orp Roos are cuckoo. Isabel and Chocolate

 

[NatJ]

For sexlinking with barring, you cannot use a barred rooster. It must be a barred hen and unbarred rooster.

 

[gunslinger33]

Thank you

My question was less related to sex linking and more to black being dominant regardless of the colors used to create the black

If I were to go back to Isabel cuckoo or silver penciled will I get just black chicks?

 

[NatJ]

For the black:
If Isabel cuckoo x silver pencilled = black chicks
Then chick x Isabel cuckoo = 1/2 black, 1/2 isabel (= diluted black)
Or, chick x silver pencilled = 1/2 black chicks, 1/2 silver pencilled chicks


For the barring:
Because the Isabel cuckoo is barred, all chicks will be barred.

Barred pullet x cuckoo rooster = all barred chicks

Barred cockerel (silver pencilled mother) x silver pencilled = half of chicks are barred. (That's half of male chicks barred, and half of female chicks barred.)

Barred cockerel (silver pencilled mother) x cuckoo = half of female chicks are barred, half not. Male chicks are all barred, but half have one copy of the gene (dark barring) and half have two copies of the gene (light barring.)

 

[birdlover2]

The advice above looks good Regardless, I like to use Kippenjungles chicken calculator:
http://kippenjungle.nl/kruisingCQ.html

 

[gunslinger33]

I’ve tried the calculator and I feel dumber than when I started.

Thanks for the info