questions on gold, silver, and cream

[turtleblossom]

Ok, so what I understand about the gold and silver genes is pretty limited, and I need some info on how to create the color cream (as in cream spangled). I know that a hen can have one gene (or is it copy?) for gold/silver. They are either just silver or just gold. But the rooster has two genes that can be either silver, gold, or one of each.

hen = s+/- is gold
S-/- is silver

roo = s+/s+ is gold
S/S is silver
S/s+ is cream

I have a cream spangled EE roo (sl Seabright hen X partrige EE roo) that I am breeding to two silver laced Wyandotte hens. I know that when I breed them I will get silver, gold, and black hens; and the cockrels will be silver, cream, and black. (of course, breeding EE's always gives you suprises)
How do I get cream hens?
I thoght about adding some Cream Brabanters, but I only want to buy hens, and they are pretty rare (despite the fact that you can get them from some major hatcheries). Why waste rare breed hens on a EE project!

 

[turtleblossom]

Know one has any info?

 

[jossanne]

I know nothing, but I'm bumping you up. Someone will come along.

 

[Henk69]

Next to het silver S/s+ you get the same effect on pure gold s+/s+ with additional cream (inhibitor of gold) gene ig/ig. This "gene" is recessive and not sexlinked. Gold hens s+/- plus ig/ig are also cream in groundcolor.

I understand the cream gene ig is pretty rare in the US.
The dilute gene Di is dominant and has a similar effect.
It is said to be in a lot of buff breeds, especially in the creamier kinds.

Then you could work with lavender but that would change the black parts too.

 

[turtleblossom]

So if I breed my cream spangeled EE to a lavender hen, I might get cream hens?

 

[Henk69]

No. All I want to say is that in a bird with 2 copies of lavender the buff parts will also be diluted to a cream tint.