Okay, so I'm going to do the math a different way according to these instructions from:
http://www.asp-inc.com/products/documents/prodinfo/a/amp128.pdf:
Dosage Level Mixing Directions
0.024% Dissolve 8 ounces of AMPROL 128 20% Soluble Powder in about five gallons of water in a 50-gallon medication barrel. Stir, then add water to the 50 gallon mark.
Stir thoroughly.
0.012% Follow same directions as above but use 4 ounces of AMPROL 128 20% Soluble Powder.
0.006% Follow same directions as above but use 2 ounces of AMPROL 128 20% Soluble Powder.
Facts
- One pack = 10 oz. (283.5 grams)
- One ounce = 28.35 grams
- One ounce of powder = ~3.5 tablespoons
- 200mg amprolium per 1 gram
My twisted math for the .024% level
If 8 ounces (28.35g x 8 = 226.8 grams) are needed for 50 gallons, then 1/50 of that is needed for 1 gallon, right?
So that would be 226.8 grams divided by 50 = 4.536 grams per gallon. (doing this as I type, so correct me if I'm wrong, please!)
So how much does a teaspoon of Corid or Amprol powder weigh? Anyone know? Well, time to break out my gram scale and do some weighing... also have a call into the mfg of Corid and I'm expecting a call back from them.
Just got a call back from them and it is 4.536 grams per gallon. He also said that it's a very safe product and the risk of overdosing is very slim.
-Kathy
Notes: Please make comments as I add stuff, 'cause I do make mistakes and would like to do this correctly.