Thanks, and glad it helped.
Quote:
Right.
Quote:
One copy barred rooster x barred hens= all sons will be barred. All sons will get the barring from their mother.. and either one or none from their one copy father. (if you later notice some boys are much lighter or darker than others, it probably is a difference between the boys having two or one copies- dose effect..)
Now for the daughters, he will give one copy to half of his daughters, and the other half won't get it.
So this adds up to 25% non-barred result.
That's from a single pairing.. if there was another rooster breeding the same hens and he is pure for barred.. the percentage could be much lower.
Breeding one copy barred rooster to buffs gives the ratio of him passing on the barring gene to half of his offspring.
Quote:
OK, think of a penny to represent a single gene. Barred for this example. Let's say the face side is the Barred gene, tails not-barred. That's an exact representation for a single copy barred rooster.
Let's make it much easier to use this penny example for one copy barred rooster x buff hen.. flip the penny once for each single egg. If it lands face up, the barred gene went into that egg. Tails up, no barring gene went into that egg.
Tails-up eggs hatch out chicks without the barring gene. It's gone, not present in any way in those. They will never show any evidence of barring. In effect, those chicks have pennies that are tails on both sides.