See "Chicken Math". I am fortunate enough to have an 80 year old barn, the end that is converted to the coop is a wind tunnel with baffles around the roosts. That means lots of birds CAN be. The first order of 30 chicks was the first element in the equation, the chick-spouse input was a second element in the equation, the second order was the third, and the third order was the fourth. This equation had a results in 88 chicks, 1 lost from each of the last two batches in the first 1 and 4 days respectively. So:
86=(Ax**a+z)+(Bx**b+y)+(Cx**c+w)+(Dx**d+v)+(Ex**e+u)+F
z=0
w=1
v=1
y=2
B=2
A=27
C=31
D=30
F=125
The key to this equation is B, b, and y. These are the factors determined by the chick-spouse. B is the quantity of residents in the chick-spouses home, b is a flunctuating value that is an equation itself involving the love component in the chick-spouse and the inherent cuteness of the chicks.
F is dollars per egg to date.
y is a quantity of 2 stones. Figure that one out yourself.
E, e, and u were added later and is a future effect of the threat of more shipments. The solution to these variables is pending.
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