I figure 2+2=5 heres how...
If
a=4
b=5
c=1
then
c=b-a/(b-a)
then
c(b-a) = (b-a)^2 (^2 means squared)
then
cb-ca=b^2 -2ab=a^2/-a^2
then
cb-ca-a^2=b^2-2ab/ab
then
ab+cb-ca-a^2=b^2-ab/-cb
then
a(b-c-a)=b(b-c-a)
then
a=b and a=4 and b=5
and 2+2=4 and 4=5 then...
2+2=5 right?
Where's my tylenol.
If
a=4
b=5
c=1
then
c=b-a/(b-a)
then
c(b-a) = (b-a)^2 (^2 means squared)
then
cb-ca=b^2 -2ab=a^2/-a^2
then
cb-ca-a^2=b^2-2ab/ab
then
ab+cb-ca-a^2=b^2-ab/-cb
then
a(b-c-a)=b(b-c-a)
then
a=b and a=4 and b=5
and 2+2=4 and 4=5 then...
2+2=5 right?
Where's my tylenol.
Last edited: