Question on Lavender genetics...

akpeeps

Songster
11 Years
Joined
Aug 25, 2008
Messages
306
Reaction score
5
Points
129
Location
Wasilla, Alaska
Okie dokey, I will be getting my chicks/chickens in a few weeks. Blue, Splash, and possibly a black roo. All will carry the lavender gene. Can someone help me out with the breakdown on what would be produced? Percentage with no lavender, one copy, or two. Or would all chicks have at least one copy?
I thought I saw somewhere that the breakdown would be 25% no copy, 50% with one copy, and 25% with two copies. I know black is dominant, but any combo that may stack the deck in my favor?

I'm liking the black roo, with possibly Blue and Splash hens/pullets (if they're available).

If I get the Splash roo should I get at least one black hen?

Science class/genetics was many, many moons ago.

Thanks for any help!
 
It's possible for them to carry both blue & lavender. They are independent genes.
Lavender is a simple autosomal recessive.
Blue is the heterozygous form of blue & not blue.
If a blue bird carried one lavender gene it would not show.
I shouldn't have thought it particularly desirable to have both in the same bird but it happens.

IMO lavender & splash in the same bird makes a nasty grubby looking white colour.

From breeding two birds each carrying one lavender gene. The 25/50/25 works with only 25% showing lavender.
Amongst those figures the various combinations of blue & non blue will also be occurring.
 
hmm.png
Hmmm, that's what I was told. They all carry one copy of the lavender gene. Soooo, they can't/don't inherit the lavender gene from a lavender parent? Even if the other parent was blue or splash?

If the blues and splashes can't/don't carry that gene, what color(s) carries it? Besides lavenders (self blues), which I know breed true lav to lav. At least one parent has to carry it.

So a lavender bred to a black/blue/splash will produce what? At least one copy is going to be passed to some of the chicks. Right?
Now I'm really confused.

Hmm, I think Appaloosa color genetics is much easier to understand.
 
If the father has one copy and the mother has one copy of Lav-50% babys will be Lav and Lav will cover black blue and splash 50% will be black blue and splash
 
To get lavender birds both parents have to carry lavender. A lavender crossed to a bird which is neither lavender or carrying a recessive lavender gene will not show lavender but it will be carrying the gene.
Blue & splash work differently. The blue gene is incompletely dominant & will show as blue when one blue gene is present & will show as splash if two blue genes are present.
A bird which has two blue genes (i.e. splash) & also has two genes for lavender, in my opinion, looks nasty.

If you have blue & splash birds each also carrying one lavender gene, approx 25% of the offspring ought to be lavender but they will also be blue or splash in quantities in the region of 50-50.
 
big_smile.png
:)Thanks, that's what I thought.

I really like the black rooster. With the black being a dominant gene, does that necessarily increase the percentage of black chicks?
 
Quote:
Well, black may or may not be a dominant allele. There are multiple types of "black" and not all are dominant. What breed are we talking about?

Anyways, blue dilutes black pigment, so if you really wanted to claim dominance of one gene over another (please don't), I could make a case of blue being dominant over black.
tongue.png
However in this discussion we are not really talking about "black," but rather about "not-blue." Specifically we are talking about a bird whose genotype with respect to the blue gene is bl,bl. All their progeny will inherit bl. Whether they are black or blue will depend on which allele of the blue gene they inherit from the other parent. If the other parent is also black, the chicks will be black. If the other parent is blue it will be 50/50 and if the other parent is splash all chicks will be blue.


They all carry one copy of the lavender gene. Soooo, they can't/don't inherit the lavender gene from a lavender parent? Even if the other parent was blue or splash?

Lavender is denoted lav; not-lavender is denoted Lav. If a parent has one copy of lavender (Lav, lav), then half their offspring will inherit Lav and the other half will inherit lav.

Likewise if a parent is blue (Bl,bl) half their offspring will inherit Bl (blue) and half will inherit bl (not-blue). If the parent is splash (Bl,Bl) all their progeny will inherit Bl.

Note that all the chicks will have some combination of two alleles of the lavender gene and two alleles of the blue gene. Kind of like you can have red hair and also have blue eyes; or brown hair and blue eyes, or blonde hair and brown eyes. The two genes are unrelated to each other--competely independent.​
 
Thanks Sonoran Silkies, that helps a lot. The extent of what I remember about genetics is using a Punnet square in high school biology class to work out genotype and phenotype. It's been a verrrry long time.

What breed are we talking about?

Silkies

Specifically we are talking about a bird whose genotype with respect to the blue gene is bl,bl. All their progeny will inherit bl. Whether they are black or blue will depend on which allele of the blue gene they inherit from the other parent. If the other parent is also black, the chicks will be black. If the other parent is blue it will be 50/50 and if the other parent is splash all chicks will be blue.

So, bl/bl would be my black roo, Bl/bl would be my blue hen.

Bl/bl

bl Bl bl

bl Bl bl

= 50/50


Lavender is denoted lav; not-lavender is denoted Lav. If a parent has one copy of lavender (Lav, lav), then half their offspring will inherit Lav and the other half will inherit lav.

What would that look like added to the above?
In theory, wouldn't that give me the possiblity of 25% lavender and the rest 50/50 blue and black?
Am I even close? Sorry to be a pain.​
 

New posts New threads Active threads

Back
Top Bottom