Toddlers are Quackers

[DwayneNLiz]

Here is the answer, once and for all, on the answer to 2 + 2.......



I'm afraid I can't take credit for this.

Let a & b each be equal to 1. Since a ^ b are equal,

b^2 = ab

Since a equals itself, it is obvious that

a^2 = a^2

Subtract equation 1 from equation 2. This yeilds

(a^2) - (b^2) = (a^2)-ab

We can factor both sides of the equation; (a^2)-ab equals a(a-b). Likewise, (a^2)-(b^2) equals (a + b)(a - b) (Nothing fishy is going on here. Ths statement is perfectly true. Plug in numbers and see for yourself!) Substituting into the equation 3 , we get

(a+b)(a-b) = a (a-b)

So far, so good. Now divide both sides of the equation by (a-b) and we get

a + b = a

b = 0

But we set b to 1 at the very beginning of this proof, so this means that

1 = 0

Now we can use this general idea and apply it to two. and can alter the number into any number. However the altered number can not be more than 1 away from the orginal number. therefore A+B= 5
A= 2 B=3

To the power of what?

. (a^2) - (b^2) = (a^2)-ab
(A to the power of 2) - (b to the power of 2 = (a to the power of 2) - ab

 

[Chaos18]

. (a^2) - (b^2) = (a^2)-ab
(A to the power of 2) - (b to the power of 2 = (a to the power of 2) - ab

So you drank some coffee?

 

[DwayneNLiz]

So you drank some coffee?

Nope not yet, it is at home in the pot waiting to be turned into ice coffee

I had pancakes and wine

 

[BantyChooks]

So you drank some coffee?

I saw that before you edited it.

 

[Chaos18]

Nope not yet, it is at home in the pot waiting to be turned into ice coffee

I had pancakes and wine

And the verdict on the wine is?

 

[DwayneNLiz]

I saw that before you edited it.

What'd it say

 

[Chaos18]

I saw that before you edited it.

Saw what?

 

[DwayneNLiz]

And the verdict on the wine is?

I didn't have the wine unless u count real syrup as wine

 

[BunnynChicks]

Quote:

I can't do math. Is that better?

 

[BullChick]

Here is the answer, once and for all, on the answer to 2 + 2.......



I'm afraid I can't take credit for this.

Let a & b each be equal to 1. Since a ^ b are equal,

b^2 = ab

Since a equals itself, it is obvious that

a^2 = a^2

Subtract equation 1 from equation 2. This yeilds

(a^2) - (b^2) = (a^2)-ab

We can factor both sides of the equation; (a^2)-ab equals a(a-b). Likewise, (a^2)-(b^2) equals (a + b)(a - b) (Nothing fishy is going on here. Ths statement is perfectly true. Plug in numbers and see for yourself!) Substituting into the equation 3 , we get

(a+b)(a-b) = a (a-b)

So far, so good. Now divide both sides of the equation by (a-b) and we get

a + b = a

b = 0

But we set b to 1 at the very beginning of this proof, so this means that

1 = 0

Now we can use this general idea and apply it to two. and can alter the number into any number. However the altered number can not be more than 1 away from the orginal number. therefore A+B= 5
A= 2 B=3

try it sitting down......

get this.

they expect me to have a social life on my time.......

that is crazy.

Seriously!

I agree completely.....

heck, here I go back again.......

enjoy yourselves.

I'm tired of doing that.

Don't let the man keep you down.

Toodles.

What if that's what he likes?

Nope not yet, it is at home in the pot waiting to be turned into ice coffee

I had pancakes and wine

Yeay!