I have noticed in the chicken calculator:
If I create a bird with E/? (Extended Black plus any other allele) and I/i+ (one gene for Dominant White), the image shows it as white.
But if I take that same bird and add mo/mo (two genes for mottling), the image shows it with spots of black.
Making it homozygous for Dominant White (I/I) makes the black spots go away again. Making it homozygous for lack of Dominant White (i+/i+) makes it go black with little white dots (mottled). Those make sense.
I'm puzzled by the idea that a mottled bird with one Dominant White gene would show more black than a solid black bird with one Dominant White gene. I can sort-of see why the mottling gene could cause the black to be arranged differently.
Do you know if this is how it actually works? I've thought of testing it by crossing a Golden Neck d'Uccle with the solid Black and the Mottled variety of some breed (one set of chicks mo/mo, other set Mo+/mo, all chicks I/i+ and E/?) But I haven't had a chance to try it, and if the answer is already well known I probably never will bother.
I did wonder if it's some sort of a glitch in the calculator, but I think it is more likely to be showing an actual known effect that I just hadn't learned about.