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(Unimportant) confusing color/pattern names

Db (Dark Brown) is apparently named for the effect it caused on the color of chick down when it was first being researched. It has other effects on the adult feathering. I don't think it always makes brown in the chick down either. (Another name that doesn't entirely make sense!)
Yeah, using the word Ginger makes a lot more sense than Db but it doesn't match the gene! But at least there are Ginger Red Games! No birds with Db are actually called Dark Brown.
 
To be fair, not all Black x Dominant white will give you paint. They all will probably have some black but some will be predominately white.
I have noticed in the chicken calculator:
If I create a bird with E/? (Extended Black plus any other allele) and I/i+ (one gene for Dominant White), the image shows it as white.

But if I take that same bird and add mo/mo (two genes for mottling), the image shows it with spots of black.

Making it homozygous for Dominant White (I/I) makes the black spots go away again. Making it homozygous for lack of Dominant White (i+/i+) makes it go black with little white dots (mottled). Those make sense.


I'm puzzled by the idea that a mottled bird with one Dominant White gene would show more black than a solid black bird with one Dominant White gene. I can sort-of see why the mottling gene could cause the black to be arranged differently.


Do you know if this is how it actually works? I've thought of testing it by crossing a Golden Neck d'Uccle with the solid Black and the Mottled variety of some breed (one set of chicks mo/mo, other set Mo+/mo, all chicks I/i+ and E/?) But I haven't had a chance to try it, and if the answer is already well known I probably never will bother.

I did wonder if it's some sort of a glitch in the calculator, but I think it is more likely to be showing an actual known effect that I just hadn't learned about.
 
I have noticed in the chicken calculator:
If I create a bird with E/? (Extended Black plus any other allele) and I/i+ (one gene for Dominant White), the image shows it as white.

But if I take that same bird and add mo/mo (two genes for mottling), the image shows it with spots of black.

Making it homozygous for Dominant White (I/I) makes the black spots go away again. Making it homozygous for lack of Dominant White (i+/i+) makes it go black with little white dots (mottled). Those make sense.


I'm puzzled by the idea that a mottled bird with one Dominant White gene would show more black than a solid black bird with one Dominant White gene. I can sort-of see why the mottling gene could cause the black to be arranged differently.


Do you know if this is how it actually works? I've thought of testing it by crossing a Golden Neck d'Uccle with the solid Black and the Mottled variety of some breed (one set of chicks mo/mo, other set Mo+/mo, all chicks I/i+ and E/?) But I haven't had a chance to try it, and if the answer is already well known I probably never will bother.

I did wonder if it's some sort of a glitch in the calculator, but I think it is more likely to be showing an actual known effect that I just hadn't learned about.
Oh yeah, that is weird, and definitely a genuine error with the calculator.
 
Oh yeah, that is weird, and definitely a genuine error with the calculator.
Do you have personal knowledge of this, or a source that talks about it? What you say does match what I'm inclined to think, but I'd be happier if I can actually check it somehow. (I've been caught before with things that sound right but are actually wrong.)
 
Do you have personal knowledge of this, or a source that talks about it? What you say does match what I'm inclined to think, but I'd be happier if I can actually check it somehow. (I've been caught before with things that sound right but are actually wrong.)
Well, Henk himself has said his calculator isn't perfect and has errors...
No, I don't have any evidence, though.
But this has been discussed before...
https://www.backyardchickens.com/threads/are-anconas-just-mottled-leghorns.1485057/post-24765752
 

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