Wrath's Marans

[z3lda3]

I have no idea... That's wayyyyy over my head. I would suggest posting a new thread asking that question.

Orrrr I could just keep breeding him with my other hens. And see what I get, like a Cracker Jack prize. Ha I’d end up with so. Many. Chickens. And probably not one single white one.

 

[BlueTheBrahma]

Ok, so if I wanted Gomez the white Cochin, to have his white coloring would it even be possible?
His first son, looks like Fred a mix of black and red, goldy, his second son is completely barred, the mama is a legbar, and his daughter is a solid black fizzled bantam, her mother is an all white frizzled bantam. I wanted his white bantam Cochins, but he’s just giving me everything but. Is it possible his white gene is so recessive it’ll never come out in his off spring?

Yes, it is recessive white. The only way you will get white offspring is breeding him to birds carrying recessive white or dominant white, ideally recessive. Or you breed him to his daughters, or breed his daughters to his sons.

That’s what recessive means, it will not be expressed unless a second copy is inherited from the other parent.

 

[wrathsfarm]

Yes, it is recessive white. The only way you will get white offspring is breeding him to birds carrying recessive white or dominant white, ideally recessive. Or you breed him to his daughters, or breed his daughters to his sons.

That’s what recessive means, it will not be expressed unless a second copy is inherited from the other parent.

This is good stuff as I don't fully understand the Recessive gene.
By breeding Poppy to Solo, all his daughters will be carrying recessive white? Not all expressing it.
By explanation....
I'm assuming some will be just be hiding it? As in they're Black Silver but carrying the Recessive white gene but a chance I can still get a White chick in that hatch? Is there a percentage possibilty associated with this.

Now, by back crossing the Black Silver daughters to Poppy, these will all be white?
And the White daughters back crossed to Poppy are pure White 100%.

Did I get right?

 

[BlueTheBrahma]

This is good stuff as I don't fully understand the Recessive gene.
By breeding Poppy to Solo, all his daughters will be carrying recessive white? Not all expressing it.
By explanation....
I'm assuming some will be just be hiding it? As in they're Black Silver but carrying the Recessive white gene but a chance I can still get a White chick in that hatch? Is there a percentage possibilty associated with this.

Now, by back crossing the Black Silver daughters to Poppy, these will all be white?
And the White daughters back crossed to Poppy are pure White 100%.

Did I get right?

Yes I think you got this right.

If Solo is C/C (no recessive white allele) then all the offspring are C/c, carrying it but not showing it.

Attentively Solo could be C/c herself, meaning half the offspring are carriers (C/c) and half pure white (c/c).

Yes, breeding the white offspring to Poppy will get you pure white marans (as only c alleles are present). You’d then be able to focus on the shade of white and leg colour if necessary.

If non of the offspring are white, then breed Poppy to his BSM daughters and you will get half white offspring, half carriers, then you can breed the whites together for pure F2s.

I think you got this correct, I just thought I’d lay out the different circumstances for you.
Hope this makes sense.

 

[BlueTheBrahma]

For simple recessive genes (I’m using R as an example, R is dominant and r is recessive):

R/R: non carrier, pure for dominant allele (e.g not recessive white). Shows dominant phenotype.

R/r: carrier, looks like the non carrier but can pass the recessive on to offspring. Shows dominant phenotype.

r/r: shows recessive phenotype (e.g recessive white or lavender)

Breed two non carriers, you will never get it.
R/R x R/R = R/R (100%)

Breed a carrier to a non carrier, you still never get it.
R/r x R/R = R/R (50%) and R/r (50%)

Breed a pure recessive to a non carrier, still won’t get it.
r/r x R/R = R/r (100%)

Breed two carriers, you will get some.
R/r x R/r = R/R (25%), R/r (50%) and r/r (25%)

Breed two pure recessives, you only get the same.

r/r x r/r = r/r (100%)

I hope this breaks it down to make it easier rather than making it seem more complicated!

 

[wrathsfarm]

Yes I think you got this right.

If Solo is C/C (no recessive white allele) then all the offspring are C/c, carrying it but not showing it.

Attentively Solo could be C/c herself, meaning half the offspring are carriers (C/c) and half pure white (c/c).

Yes, breeding the white offspring to Poppy will get you pure white marans (as only c alleles are present). You’d then be able to focus on the shade of white and leg colour if necessary.

If non of the offspring are white, then breed Poppy to his BSM daughters and you will get half white offspring, half carriers, then you can breed the whites together for pure F2s.

I think you got this correct, I just thought I’d lay out the different circumstances for you.
Hope this makes sense.

For simple recessive genes (I’m using R as an example, R is dominant and r is recessive):

R/R: non carrier, pure for dominant allele (e.g not recessive white). Shows dominant phenotype.

R/r: carrier, looks like the non carrier but can pass the recessive on to offspring. Shows dominant phenotype.

r/r: shows recessive phenotype (e.g recessive white or lavender)

Breed two non carriers, you will never get it.
R/R x R/R = R/R (100%)

Breed a carrier to a non carrier, you still never get it.
R/r x R/R = R/R (50%) and R/r (50%)

Breed a pure recessive to a non carrier, still won’t get it.
r/r x R/R = R/r (100%)

Breed two carriers, you will get some.
R/r x R/r = R/R (25%), R/r (50%) and r/r (25%)

Breed two pure recessives, you only get the same.

r/r x r/r = r/r (100%)

I hope this breaks it down to make it easier rather than making it seem more complicated!

This helps tremendously. Screenshotted for my notes, thank you.

 

[BlueTheBrahma]

This helps tremendously. Screenshotted for my notes, thank you.

Brilliant.
You might recognise that 25, 25, 50% split from breeding two blues, that’s because it’s the exact same numerical reasoning. The only difference in that case is that blue and splash are co-dominant (neither is fully recessive), so the middle combination, blue, occurs rather than one being masked entirely. So instead of having carriers, you have blues.
Ignoring sex-linkage, most crossings occur in this nature in regards to individual genes, the resulting phenotype just depends on the dominance of the allles.

 

[BlueTheBrahma]

In other news I got my first >4 oz (114g) egg today.

 

[wrathsfarm]

Brilliant.
You might recognise that 25, 25, 50% split from breeding two blues, that’s because it’s the exact same numerical reasoning. The only difference in that case is that blue and splash are co-dominant (neither is fully recessive), so the middle combination, blue, occurs rather than one being masked entirely. So instead of having carriers, you have blues.
Ignoring sex-linkage, most crossings occur in this nature in regards to individual genes, the resulting phenotype just depends on the dominance of the allles.

I really appreciate you explaining it out in great detail.

 

[wrathsfarm]

In other news I got my first >4 oz (114g) egg today.

Holy moly...