Using this genetic system, chocolate would be two semipearled genes and two dark dun genes. Also, it sounds like you are talking about codominance at the semi-pearling allele, but this would be following simple Mendelian genetics, so they would need to be homozygous for semi-Pearling to appear semi-pearled. So, Chocolate would have two dark dun genes and two semipearl genes. Coral blue would have two lavender genes and two semipearl genes. If all other genes were wild type, resulting progeny would be homozygous for semi-pearl, heterozygous for dark dun, and heterozygous for lavender. Because dun and lavender are recessive to wild type (Pearl Gray), phenotypically, they would have the Pearl Gray base color and be semipearled, which would show as Royal Purple. I did find one paper that reports on test breeding for some of this, but it’s older and lacking light dun, attenuate, bronze, pinto, etc. I’ve tried to attach the paper, but am also including a link:
https://academic.oup.com/jhered/article-pdf/87/2/138/6452301/87-2-138.pdf