Toddlers are Quackers

It's Monday my brain is off until tomorrow
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Here is the answer, once and for all, on the answer to 2 + 2.......



I'm afraid I can't take credit for this. :gig

Let a & b each be equal to 1. Since a ^ b are equal,

b^2 = ab

Since a equals itself, it is obvious that

a^2 = a^2

Subtract equation 1 from equation 2. This yeilds

(a^2) - (b^2) = (a^2)-ab

We can factor both sides of the equation; (a^2)-ab equals a(a-b). Likewise, (a^2)-(b^2) equals (a + b)(a - b) (Nothing fishy is going on here. Ths statement is perfectly true. Plug in numbers and see for yourself!) Substituting into the equation 3 , we get

(a+b)(a-b) = a (a-b)

So far, so good. Now divide both sides of the equation by (a-b) and we get

a + b = a

b = 0

But we set b to 1 at the very beginning of this proof, so this means that

1 = 0

Now we can use this general idea and apply it to two. and can alter the number into any number. However the altered number can not be more than 1 away from the orginal number. therefore A+B= 5
A= 2 B=3
 

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