Toddlers are Quackers

[Chaos18]

Here is the answer, once and for all, on the answer to 2 + 2.......



I'm afraid I can't take credit for this.

Let a & b each be equal to 1. Since a ^ b are equal,

b^2 = ab

Since a equals itself, it is obvious that

a^2 = a^2

Subtract equation 1 from equation 2. This yeilds

(a^2) - (b^2) = (a^2)-ab

We can factor both sides of the equation; (a^2)-ab equals a(a-b). Likewise, (a^2)-(b^2) equals (a + b)(a - b) (Nothing fishy is going on here. Ths statement is perfectly true. Plug in numbers and see for yourself!) Substituting into the equation 3 , we get

(a+b)(a-b) = a (a-b)

So far, so good. Now divide both sides of the equation by (a-b) and we get

a + b = a

b = 0

But we set b to 1 at the very beginning of this proof, so this means that

1 = 0

Now we can use this general idea and apply it to two. and can alter the number into any number. However the altered number can not be more than 1 away from the orginal number. therefore A+B= 5
A= 2 B=3

What does the ^ mean?

 

[BantyChooks]

What does the ^ mean?

^ means and.

 

[Chaos18]

^ means and. So it means a and b.

So then why not write "and" instead of putting the ^? Would be a lot less confusing.

 

[BantyChooks]

So then why not write "and" instead of putting the ^?  Would be a lot less confusing.

Because it isn't confusing enough!

 

[Chaos18]

Because it isn't confusing enough!

It made perfect sense though.......except for the ^

 

[BantyChooks]

It made perfect sense though.......except for the ^

That's why they throw it in. To confuse you.

 

[Chaos18]

That's why they throw it in. To confuse you.

That wasn't very nice of them.

 

[BunnynChicks]

Here is the answer, once and for all, on the answer to 2 + 2.......



I'm afraid I can't take credit for this.

Let a & b each be equal to 1. Since a ^ b are equal,

b^2 = ab

Since a equals itself, it is obvious that

a^2 = a^2

Subtract equation 1 from equation 2. This yeilds

(a^2) - (b^2) = (a^2)-ab

We can factor both sides of the equation; (a^2)-ab equals a(a-b). Likewise, (a^2)-(b^2) equals (a + b)(a - b) (Nothing fishy is going on here. Ths statement is perfectly true. Plug in numbers and see for yourself!) Substituting into the equation 3 , we get

(a+b)(a-b) = a (a-b)

So far, so good. Now divide both sides of the equation by (a-b) and we get

a + b = a

b = 0

But we set b to 1 at the very beginning of this proof, so this means that

1 = 0

Now we can use this general idea and apply it to two. and can alter the number into any number. However the altered number can not be more than 1 away from the orginal number. therefore A+B= 5
A= 2 B=3

I can't stand math.

 

[Tumbling K]

I can't stand math.

try it sitting down......

 

[Chaos18]

Oh

Bert. Nice of you to join us.