what game breed am i ?

Spangled and black do make mottled, but they're not OEG. The yellow legs and pea comb give it away.. Most likely they're American games, usually called OEG's because they look somewhat similar to people who aren't familiar with them. They also sometimes have dark facial skin. If she was part sumatra, i would expect her legs to be darker, and probably a walnut instead of pea comb (that is of course if it were pure OEG and not Americans which can throw many combs while OEG have only single). But that is just a guess, most f1 sumatras i've seen come the sumatra look as well.

-Daniel.
 
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he said no , she is pure oeg , but was in with the Black Sumatra roo (he was trying to make mottled Sumatras and he did so he sold the hen to me ) I am confused Are you saying its pure oeg or a mottled sumatra
 
he said no , she is pure oeg , but was in with the Black Sumatra roo (he was trying to make mottled Sumatras and he did so he sold the hen to me )
I am confused are you saying she is pure OEG or mottled sumatra
 
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If she has a pea comb she's not "pure oeg". If she was an oeg she'd have a single comb. Spangled X Black OEG wouldn't produce a Mottled bird & it also would not produce yellow legs. She's obviously a cross of some sort.
 
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If she has a pea comb she's not "pure oeg". If she was an oeg she'd have a single comb. Spangled X Black OEG wouldn't produce a Mottled bird & it also would not produce yellow legs. She's obviously a cross of some sort.

Doesn't it depend on what the black bird is hiding? Seems like you could still feasibly get a mottled bird out of this cross.
 
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If she has a pea comb she's not "pure oeg". If she was an oeg she'd have a single comb. Spangled X Black OEG wouldn't produce a Mottled bird & it also would not produce yellow legs. She's obviously a cross of some sort.

Doesn't it depend on what the black bird is hiding? Seems like you could still feasibly get a mottled bird out of this cross.

Since it sounds like the varieties are mixed in together, yes, it is possible. Mottle does not usually show unless present in two copies, so let's assume that the black parent carried a copy of mottle. (The bird pictured is way too mottled to be a leaky one-copy mottle.) As a solid black bird, that parent may well be extended black. Spangled in this case is a mottled wildtype bird. Extended black is dominant to wildtype and mottle inherited from both parents gives a mottled bird.

I do agree that she is not OEGB--just does not look the part at all.
 

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