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Edit: Do you have any pictures of what a single mottled gene (carried but not expressed) Ameraucana looks like?
You would have a solid colored bird, as a single copy of the gene does not express itself.
So the bird in this case, would be Black.
Can someone explain this? I have a Lavender Ameraucana roo that I got as a young chick and have been growing out specifically to use with my mixed flock of girls for creating Easter Egger chicks. I've done three small batches of chicks so far and ALL of the chicks have been either Blue or Black. I thought that the mothers would have some influence on chick color but so far, not at all. I've hatched chicks from a white EE, a blue EE, a brabanter/spitz/easter egger hen, a welsummer, and an Australorp hen to name a few. I expected black from the Australorp match and blue from the blue easter egger but even the chick from the welsummer is black.
Are there any blues in your hens ? Let me try to explain your results . Lavender is a recessive dilution of black . So it takes 2 copies of the lavender gene to see lavender . One copy is a black called a lavender split . So all your chicks should be black . You must have blue in some of the hens to be getting blue . If not then your rooster is blue or a lavender carrying blue . This is why it is not recommended to mix lavender and blue . It just makes it hard to tell them apart in future breeding .
I do have a blue Easter egger hen as I mentioned and I expected the blue chicks from her. I just didn't realize that every single other chick would be black. I hatched chicks from a white EE, a brabanter/spitz/easter egger hen, a welsummer. If I want some of the mother's colors to show through, what color of Am do I need for a Roo?