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If both parents are homozygous on all alleles where that is possible you have these three possibilities

50% AABBCcchdDDeeEnen (broken black agouti non-extention)

25% AABBCcchdDDeeenen (black agouti non-extention)

25% AABBCcchdDDeeEnEn (Charlie black agouti non-extention) -this one would be particularly interesting since Charlie's already have most of their pigment removed, plus the addition of the non-extention which will further remove dark pigmentation


The most complicated scenario leads to 156 unique allelic combinations.

This is the 5 trait cross with locus’ A-E, but then you have to multiple this Punnet Square by three (technically by four but two quarters will be broken so it is not unique allelic combinations) to account for the En locus.

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She's munching on some fresh hay I just gave her... Then taking the rest to her nest 😂🤦‍♀️
 

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