Try this one instead:
http://marsa_sellers.tripod.com/geneticspages/page3.html
I think from the responses on the other thread; everyone was confused--it isn't written properly if you're confused!!
J-Lo....well, it really depends on her children, although sometimes individuals who are homozygous for a trait will display the trait to a higher degree than heterozygous individuals. An example would be pinto horses--some horses who are homozygous for pinto will display the trait to a higher degree--which, in this example, means little tiny spots around the pinto marking....here's a link--check out the second and third pictures
http://blacktiearabians.com/tiebreaker/index.html (no affiliation whatsoever, just the first google hit)
Edited to add: I'm not sure if I was entirely clear about sex-links. In some cases, females will carry a dominant gene on one X chromosome, and a recessive gene on another. In these cases, half of their male offspring will have a "sex-linked" trait (I think some may be calling it an "x-linked" trait now.)
This is because if you think about it, females only have the X chromosome to give their offspring. So all unfertilized eggs will have just one X. The sperm, however, has either a Y or an X--and this determines the sex of the bird. Now, if you have an individual who is heterozygous for a sex-linked trait, It must be a female who is heterozygous, males are only homozygous for sex-linked traits, because they only have the one allele!
So, males receive only the X from their mother. So if their mother is heterozygous for a sex-linked trait (e.g. color blindness) This is displayed as X^C X^c(the Cs should be superimposed) Half of her male offspring will have the trait--EVEN IF THE FATHER HAS IT! It doesn't matter for the males if he has the trait or not, because he does not give them that chromosome, at all!
If the mother again is heterozygous for the trait, and she mates with a recessive male (who would then be displaying the trait), half of her male offspring would again display the trait, as well as half of her female offspring.
To breed true in this case, you would have to use two homozygous recessive individuals to get consistently trait-displaying offspring.
*phew* I hope that clears up any confusion