Australorps breed Thread

Quote: The blue / Splash is Clear ..thanks ...
So is that why some of my chicks are Black & some are White ?
I tried to pick white rock eggs as they are the youngest . they could have also been Comet Eggs.. my Roo is a Australorp
Would the black ones have 2 black Genes and the white ones 2 dominant white genes? as all the white ones have some black feathers
I thought maybe black chicks were comet babies & white chicks were white rock babies
 
The blue / Splash is Clear ..thanks ...

So is that why some of my chicks are Black & some are White ?
I tried to pick white rock eggs as they are the youngest . they could have also been Comet Eggs.. my  Roo is a Australorp
Would the black ones have 2 black Genes and the white ones 2 dominant white genes? as all the white ones have some black feathers
 I thought maybe black chicks were comet babies & white chicks were white rock babies

I do not breed the colour white so I am not too experienced on this colour however if the white rocks were dominant white and they were mated with your black Australorp roo then all the resulting chicks should be white (with leakage). I would also think that the black Australorp x comets would all be black too (with some red leakage possible). So to answer your question yes you are right, the white rocks would produce white offspring and the comets would would have black offspring. I could be wrong so anyone please feel free to correct me if this is not the case. to my understanding comets are a hybrid so it would also depend on what hidden genes are hiding in the comets as you will find that different hybrid strains have different hidden genes. Hope this has helped somewhat.
 
Yes that's right, splash and white are two completely different genes. Splash is a double dose of the blue gene. Splash is essentially black diluted down by two blue genes. Therefore a Splash chick can only eventuate if the parent birds are either both blue, Blue and splash, or both splash

A black gene is written as Bl
A blue gene is written as bl

Therefore:
Black bird = Bl/Bl
Blue bird = Bl/bl
Splash bird = bl/bl

Black x Black = 100% black progeny (Bl/Bl *2 copies of black gene)

Black x Blue = 50% black progeny (Bl/Bl *2 copies of black gene) & 50% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene)

Black x Splash = 100% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene)

Blue x Blue = 25% black progeny (Bl/Bl *2 copies of black gene) & 50% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene) & 25% splash progeny (bl/bl *2 copies of blue gene)

Blue x Splash = 50% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene) & 50% splash progeny (bl/bl *2 copies of blue gene)

Splash x Splash = 100% splash progeny (bl/bl *2 copies of blue gene)


White on the other hand comes in two forms; Dominant white and recessive white. It is common for dominant white birds to have black leakage however recessive white birds are almost always white providing they have two doses of the recessive white gene. If a bird only has one copy of recessive white then the white will not express at all and the bird will just be a carrier of that gene.
Hope that helps explain it a little clearer and I have not confused you :)

I love how that works. You can use this dominant/recesive in anything. Learned it in college.
 
Yes that's right, splash and white are two completely different genes. Splash is a double dose of the blue gene. Splash is essentially black diluted down by two blue genes. Therefore a Splash chick can only eventuate if the parent birds are either both blue, Blue and splash, or both splash

A black gene is written as Bl
A blue gene is written as bl

Therefore:
Black bird = Bl/Bl
Blue bird = Bl/bl
Splash bird = bl/bl

Black x Black = 100% black progeny (Bl/Bl *2 copies of black gene)

Black x Blue = 50% black progeny (Bl/Bl *2 copies of black gene) & 50% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene)

Black x Splash = 100% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene)

Blue x Blue = 25% black progeny (Bl/Bl *2 copies of black gene) & 50% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene) & 25% splash progeny (bl/bl *2 copies of blue gene)

Blue x Splash = 50% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene) & 50% splash progeny (bl/bl *2 copies of blue gene)

Splash x Splash = 100% splash progeny (bl/bl *2 copies of blue gene)


White on the other hand comes in two forms; Dominant white and recessive white. It is common for dominant white birds to have black leakage however recessive white birds are almost always white providing they have two doses of the recessive white gene. If a bird only has one copy of recessive white then the white will not express at all and the bird will just be a carrier of that gene.
Hope that helps explain it a little clearer and I have not confused you
smile.png


MrsB
 
What a relief when all the Littles (3 months) and all the Bigs (6 months) emerged from the coop and flocked together. :) Our integration plan WORKED!




Still working on the coop... Here's the floor. :p



Sooooooooooooon...........

MrsB
 

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