Black x Splash = lavender?

MoodyChicken

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10 Years
Feb 15, 2009
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A friend of mine just hatched two adorable Modern Game babies from a Black x Splash cross. They're two weeks old right now and appear to be Self Blue/Lavender. How does that work out? Obviously, they both carried the lav gene, but... I don't know... it's probably a really simple answer that I'm over thinking. lol. But shed some light on this, would ya?
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Splash is made from two blue genes (regular blue)

The blue genetics are:
Blue is made by 1 blue gene(Bl) and one black gene (bl)
black is made by 2 black (bl,bl) (sport in b/b/s) genes
splash is made by 2 blue genes (Bl,Bl)

So.....
splash+splash=100% splash (Bl,Bl)
splash+blue=50-50 blue (Bl,bl) and splash (Bl,Bl)
splash+black=100% blue (Bl,bl)
blue+blue= 50-25-25 for blue/black/splash (b/b/s)
blue+black=50-50 for blue (Bl,bl) and black (bl,bl)

Lavender, or self blue, is recessive, so the chicks would have to get 2 genes for self blue to be self blue. The splash is probably a lighter splash, which would make the blue chicks light.

ETA: Okay, done editing
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That's right now!
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Last edited:
splash x black usually gets Lav/Blue/Self Blue

No. Splash X Black = Blue

Lavender is also known as self-blue, and is an unrelated recessive gene. If both parents are split to lav (carry one copy), half their progeny would be blue lavender (both blue & lavender--a colour that is a composite of both)


Blue is made by 1 blue gene(Bl) and one black gene (bl)
black is made by 2 black (bl,bl)

No. bl is not correctly called black; black is at the E-allele. A better term would be "not blue."​
 
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This is incorrect, if both parents are split lav, only 25% will be visably lav, 50% will be split lav, and 25% will not carry the gene...you will not get 50% lav.
 

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