Ok, asking a few more questions to clarify on the dominant brown egg genetic. So, it seems to be all up to the hen for brown color, not at all the egg. Is this correct? Since the hen produces the brown pigment on all of her eggs, no matter the roo that covers her. So, a hen that lays white or blue eggs will never produce brown eggs, even if covered by, say, a Marans or a Wyandotte, etc. Yes? Ok, hypothetical situation as follows. Brown is a dominant gene, and most purebreed brown layers have two copies of that gene. So if a brown layer (say, EE) was covered by a white-egged breed (say, Silkie) roo, then all chicks would only carry one copy of the brown layer gene (at most; if the hen for sure carries two copies). Yes? But - correct me if I'm wrong - there is no way to tell if a chick will be a homozygous brown, single carrier, or does not carry brown (therefore white or blue) layer by the color of it's egg, because momma hen is going to cover it in brown no matter what. And in reverse - this means that, if a roo carried the brown gene, he could pass it to his chicks, but those chicks could hatch from white or blue eggs (when paired to a non-brown layer) so you wouldn't know they carried. Right? (Or is it sex-linked, and the roo can't carry that gene?) So it seems, the ONLY way to know if a chick will give brown eggs, is to raise her up and see. And there is no way to tell for a rooster. Is this correct? Thank you for all of your help. We are currently trying to breed for blue eggs, through our EE hens and our Silkie roo. Next spring we will be buying cream legbar hatching eegs, and those hatched hens will be paired in... but we have a sentimental connection to our current EExSilkie pullets (our first home-hatched chicks, from our original and RIP silkie roo, who we loved), and we don't want to exclude them from the line. But we want to find the best way to exclude the brown gene in the shortest amount of time (generations-wise).