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In very simple terms, I've heard/read that Gold Laced x Blue Splash will produce 100% BLR. But I can't believe it's that easy . . . if it were, I think everyone would have them! (If you use Blue rather than Blue Splash, offspring would appear 25/50/25, as they do in Blue x Blue.) And I'm told you should start with the reddest/most golden-laced you can find.
Brian Reeder writes on BLR in his "Color Forms" book as follows, in the section under eb Varieties Based on s+:
"Blue Laced Red - This variety is a darker version (no dilute) of Golden Laced to which one dose of blue is added to make the darker blue laced while two doses of blue are added (Bl/Bl) to make the light form of blue laced which is actually a splash laced red. The genome is eb/eb s+/s+ Ap/Ap Mh/Mh Co/Co Pg/Pg Ml/Ml Bl/bl+. The lighter colored or splash birds are the same genome except they are Bl/Bl. Some of these birds are segregating Db while "rb" is also seen in some lines. The correct name is alternately Blue Laced Mahogany Columbian Red Brown, or Blue Laced Red Brown for short, as Laced implies Co/Pg/Ml. The light version would be a Splash Laced Red Brown."
Any thoughts or interpretations of this?