nothing, they are end products(like broiler chicks) you could breed them back to either leghorn to encrease egg production but only 50% of them wil lay blue eggs the rest will be white eggers, or breed back to legbars but I dont see the point as they will have all sorts of color(white leghorns hide blue, mottling, barring and are Silver Birchen)
I was giving you guys some time to see if someone could answer it as I am not really good teacher and can get very technical so I will be as nice as possible..@Mama Bay I forgot to tell you that the hen was a Double Blue Laced Red Barnevelder, so according to the chicken color calculator, this is what you should possibly get. Since there are no pics for the girls available, I request that the experts be kind enough to explain what that genetic jargon means:
e+eb co+co+ db+db+ Pgpg+ Mlml+ Cha+Cha+ Mhmh+ di+di+ Ig+ig cb+cb+ i+i+ Blbl+ Lav+Lav+ C+C+ Mo+Mo+ B- s+- Choc+-
Gender = Female, Ratio = 1/4 = 25%, minimum of animals to breed: 4
blue patterned red incomplete quail?•Q(wildfarbig) barred Split: lemon/cream
Continue with this Female | Select for later crossings
e+eb co+co+ db+db+ Pgpg+ Mlml+ Cha+Cha+ Mhmh+ di+di+ Ig+ig cb+cb+ i+i+ Blbl+ Lav+Lav+ C+C+ Mo+Mo+ Bb+ s+s+ Choc+Choc+
Gender = Male, Ratio = 1/4 = 25%, minimum of animals to breed: 4
extended blue patterned red duckwing barred Split: lemon/cream
Continue with this Male | Select for later crossings
Gender = Female, Ratio = 1/4 = 25%, minimum of animals to breed: 4
black patterned red incomplete quail?•Q(wildfarbig) barred Split: lemon/cream
Continue with this Female | Select for later crossings
e+eb co+co+ db+db+ Pgpg+ Mlml+ Cha+Cha+ Mhmh+ di+di+ Ig+ig cb+cb+ i+i+ bl+bl+ Lav+Lav+ C+C+ Mo+Mo+ Bb+ s+s+ Choc+Choc+
Gender = Male, Ratio = 1/4 = 25%, minimum of animals to breed: 4
extended black patterned red duckwing barred Split: lemon/cream
Continue with this Male | Select for later crossings
All I can understand is half of them will have blue and other half, splash. Certainly looks like they would be double laced or at least it will be "incomplete quail" lacing on the girls. I have no idea what that means either. The boys definitely will be barred, so the boys should start looking very different as soon as they feather out (idk if the correct word is feather in or out) at 3-4 weeks of age.
That was very helpful to me! I wish I had kept more of these crosses. Now I will have to help myself with pics only!I was giving you guys some time to see if someone could answer it as I am not really good teacher and can get very technical so I will be as nice *** possible..
in the "NO IMAGE AVAILABLE" : which are Females
e+/eb : e+ is wildtype from Legbar and eb from Barnevelders
co+/co+: co+ is the wildtype counterpart of Columbian(Think about columbian wyandotte) while Co creates a columbian pattern co+ does not so the bird is left normal(duckwing pattern in this case)
db+/db+ : db+ is the wildtype counterpart of Db(dark brown) which is a powerful columbian like restrictor. while Db creates a Black Tailed Red pattern, db+ does nothing
Pg/pg+ : Pg is the Pattern gene(found on laced, double laced, spangled patterned birds) this gene comes from the Barnevelder parent, pg+ does nothing except that in this case is countering Pg, Pg/Pg birds have better pattern than Pg/pg+ birds because Pg its incompletely dominant.
Ml/ml+ : Ml stands for Melanotic, its a melanizer need it for lacing/spangled patterns, ml+ its the wild recessive counterpart and its also countering the Ml gene
Cha+/Cha+: its the wildtype counterpart of cha which stands for charcoil a recessive melanizer, none of these brids have cha
Mh/mh+: Mahogany is a very powerful red enhancer found on Barnevelder(also on RIR) and thats where this cross gets it from, mh+ its the wildtype counterpart and comes from the Legbar parent
di+/di+: stands for Dominant Dilute of gold di+ its the wildtype counterpart, neither of these birds have Di
Ig+/ig : ig its the autosomal recessive cream which is a gold diluter, thise cross will not be diluted because Ig+ its completely dominant over ig, ig from legbar and Ig+ from Barnevelder
cb+/cb+: cb+ its the wildtype counterpart of Cb dominant autosomal Champagne Blond gold diluter, none of these birds carry Cb
i+/i+: i+ is the wildtype counterpart of dominant white I/I(think about white leghorn) none of these birds carry dominant white
Bl/bl+: Bl is Blue(from barnevelder) bl+ is black, Bl/Bl birds are called splash blue
Lav+/Lav+: Lav+ is the dominant wildtype counterpart of lavender, none of these birds are lavender
C+/C+: C+ is the dominant wildtype counterpart of recessive white c/c, some lines of legbars carry recessive white, yours may or may not carry it
Mo+/Mo+: is the dominant wildtype counterpart of recessive mottling mo/mo, none of these birds(legbar or barnevelder) carry mottling
B: B stands for Dominant sexlinked Barring since you use a CL rooster on this cross your pullets are going to be B/- and roosters are going to be B/b+ males get one copy of B from Cl Sire and one copy of b+ from Barnevelder mother, pullets of this cross can only get one copy of B from father
s+/s+: s+ is the wildtype recessive sexlinked gold gene, since both parents are s+/s+ females are s+/- and males are s+/s+
How does this Translate to looks?
Males will look like a darker than usual(thanks to Melanotic and Pg) single Barred red Crele(thanks to mahogany for enhancing gold and single copy of Barring making the barring very dark) 50% will be Blue and 50% Black as in blue crele or black crele
Show Quality Barnevelder males can be very very dark making the hackle almost entirely black, but you can still see its ducking(gold/red wing triangle or secondaries)
but the males from this cross will be less dark due to melanotic not being completely dominant,
the females will also be darker than usual, this is a e+/eb based banevelder cross hen, you may see same pattern but with barring, some CL females already show some form of melanzing
another double laced wiltype pullet
Who said you were not a good teacher! This is perfectly explained. I never understood all these different lacing terms till today. I highly doubt I will find a Chocolate Partridge Wyandotte rooster. But I do have access to a Chocolate Wyandotte and a Chocolate Orpington rooster. Wyandotte is a bantam and weighs about 4.5 lbs so wondering if that will affect the size too much.double Lacing its pretty simple its the combination of the Pattern gene(Pg/Pg) and Melanotic(Ml/Ml) on a eb background, single lacing requires Columbian restrictor Co/Co
this picture from this source http://www.edelras.nl/chickengenetics/mutations1.html#gen_mut_secpattern
will give you a visual on the effect of Pg and Ml and Co on eb(same e allele found on barnevelders and wyandottes)
a simple way to create Chocolate Double laced Pullets its to use a Chocolate Partridge Wyandotte rooster (I dont know how rare they are in the USA) over a Barnevelder hens this will give you sexlinks, females will have inherited the recessive sexlinked chocolate gene so they will fully express the chocolate gene while males will not be able to disply the gene because its hidden or recessive due to the pressence of the dominant sexlinked non-chocolate gene from mother
now if you dont have access to chocolate partridge wyandotte you could also use chocolate Orp rooster but its not going to be that easy, instead of doing a F1 x F1 that will result in F2 you could try to go back to Barnevelders using the F1 Black males that are split for the choc gene, if you cross that rooster back to Barnevelder you will have 50% chance at hatching chocolate colored Barnevelder patterned pullets only pullets so you would need to hatch at least 30 eggs
. Awesome explanation and visual!double Lacing its pretty simple its the combination of the Pattern gene(Pg/Pg) and Melanotic(Ml/Ml) on a eb background, single lacing requires Columbian restrictor Co/Co this picture from this source http://www.edelras.nl/chickengenetics/mutations1.html#gen_mut_secpattern will give you a visual on the effect of Pg and Ml and Co on eb(same e allele found on barnevelders and wyandottes)a simple way to create Chocolate Double laced Pullets its to use a Chocolate Partridge Wyandotte rooster (I dont know how rare they are in the USA) over a Barnevelder hens this will give you sexlinks, females will have inherited the recessive sexlinked chocolate gene so they will fully express the chocolate gene while males will not be able to disply the gene because its hidden or recessive due to the pressence of the dominant sexlinked non-chocolate gene from mother now if you dont have access to chocolate partridge wyandotte you could also use chocolate Orp rooster but its not going to be that easy, instead of doing a F1 x F1 that will result in F2 you could try to go back to Barnevelders using the F1 Black males that are split for the choc gene, if you cross that rooster back to Barnevelder you will have 50% chance at hatching chocolate colored Barnevelder patterned pullets only pullets so you would need to hatch at least 30 eggs
Thanks, you know, some people can make some random coments on these forums(in general) and they get Thumbs up for it.. but me? I put on a very Detailed Clinic not once but many times and I just dont get them Thumbs Up, either people are so perplex by it and forget to leave a thank you "Thumbs Up" or they just dont care,
