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If you bred two smooths together and had frizzled offspring, you have just proven that your birds carry the frizzle modifier. If and only if a bird has two copies of the frizzle modifier gene can it hide the presence of the frizzle gene.
For a moment, let's pretend that the frizzle modifier gene does not exist, or if it does, iis not present at all in a flock. You will be able to tell which birds are F/F, which are F/f and which are f/f. Those who are F/F will be curlies--overly frizzled/frazzled birds. Those who are F/f will be normal frizzles and those who are f/f will not be frizzled. The following punnet squares show the possible matings and the predicted results of offspring.
CurleyXCurley 100% curley offspring
F F
F FF FF
F FF FF
CurleyXFrizzle 50% curley offspring; 50% frizzle offspring
F f
F FF Ff
F FF Ff
CurleyXNon-frizzle 100% frizzle offspring
f f
F Ff Ff
F Ff Ff
FrizzleXFrizzle 25% curley offspring; 50% frizzle offspring; 25% non-frizzle offspring
F f
F FF Ff
f Ff ff
FrizzleXNon-frizzle 50% frizzle offspring; 50% non-frizzle offspring
f f
F Ff Ff
f ff ff
Non-frizzleXNon-frizzle 100% non-frizzle offspring
f f
f ff ff
f ff ff
Okay, now let's consider the frizzle modifier gene--this gene "unfrizzles" a bird; however, as a recessive gene it has an effect only when the bird carries two copies.
A genetically frizzled bird (Ff) who has a double dose of this modifier gene will appear to not be frizzled; a genetically curley bird (FF) will appear to be frizzled (Ff), not curley.
If you mate a genetically frizzled bird (who appears to be non-frizzled due to a double dose of the frizzle modifier gene) to a genetically non-frizzled bird who does not carry the modifier gene, the offspring will receive only one copy of the modifier gene, thus turning OFF its frizzle reduction affect. Half the offspring will be frizzled, seemingly from a non-frizzle to non-frizzle mating.