En anglais (in English)
Thank you for your responses.
I note that to make a correct table (Punnett square), it is necessary to count both partners.
Midnight Black shoulder cock: M/M:No/No:BS/BS
Midnight White Eye split Black Shoulder hen: M/M:We/We:BS/Nw
I ask myself, if for example, I want to cross my hen with a classic India Blue homozygous IB/IB --
That will give me IB/M/We/BS and IB/M/We/Nw which is to say all blue, but split M (midnight) WE (white eye) and BS (black shoulder).
[Not translating here, but a comment from me, Garden Peas: I think only half the chicks would be split BS, mom is split BS, she will only give the BS gene to one chick of two. I think it is listed correctly above.]
[@Jack07
, de moi, je pense que ne la moitié des poussins seront divisés nigripens car la paonne soit divisé soi même, alors elle ne le donnent qu'a un poussin de deux. Je pense que c'est correct au dessus.]
If I wish to make it more complicated...
Now I believe that my hen has, for example, cameo!!!
If I understand correctly, I will obtain all blues split cameo, split midnight, split WE, split BS
An additional problem -- cameo lies on the sex gene?
After that, I think I will thoroughly understand the genetics.
I do not have time this evening to translate. Thank you.
Hope this helps,
Peas