Yes that's right, splash and white are two completely different genes. Splash is a double dose of the blue gene. Splash is essentially black diluted down by two blue genes. Therefore a Splash chick can only eventuate if the parent birds are either both blue, Blue and splash, or both splash
A black gene is written as Bl
A blue gene is written as bl
Therefore:
Black bird = Bl/Bl
Blue bird = Bl/bl
Splash bird = bl/bl
Black x Black = 100% black progeny (Bl/Bl *2 copies of black gene)
Black x Blue = 50% black progeny (Bl/Bl *2 copies of black gene) & 50% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene)
Black x Splash = 100% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene)
Blue x Blue = 25% black progeny (Bl/Bl *2 copies of black gene) & 50% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene) & 25% splash progeny (bl/bl *2 copies of blue gene)
Blue x Splash = 50% blue progeny (Bl/bl *1 copy of black gene and 1 copy of blue gene) & 50% splash progeny (bl/bl *2 copies of blue gene)
Splash x Splash = 100% splash progeny (bl/bl *2 copies of blue gene)
White on the other hand comes in two forms; Dominant white and recessive white. It is common for dominant white birds to have black leakage however recessive white birds are almost always white providing they have two doses of the recessive white gene. If a bird only has one copy of recessive white then the white will not express at all and the bird will just be a carrier of that gene.
Hope that helps explain it a little clearer and I have not confused you
