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I'm not sure if I understand what you are asking, and maybe someone else will be able to answer you better, but lavender doesn't "dilute" color. It is hidden, so if you for example, bred blacks to lavs, you end up with splits, so black birds that carry the lavender gene. When you breed those splits together, you will get some lavs and some blacks. It's like recessive white in the Faverolles, if you have two salmon faverolles that carry the recessive white gene, when you breed them, you can get some whites, and some salmons that carry the recessive white gene, or some salmons that don't carry the recessive white gene. But the parents both still look salmon, not diluted at all...
Is that what you are asking??
Actually I must have no understanding at all of the lavender gene because I thought it was a recessive dilutant that worked on both black and red ; blacks being called self blues or lavender depending on breed ; and porcelain or isabel , depending on pattern , when expressed by diluting both red and black .
ETA : Naturally a recessive dilutant would not be expressed in a split ; the splits having only one copy of it .
IF I understand how lavender works , I
still don't know if its possible for both blue and lavender to be expressed in the same bird .
IFFF I understand what you are asking.... A blue Ameraucana with two copies of the self-blue (aka lavender) gene would be a lavender. What I think people are unsure of is if this would result in a even lighter lavender. I don't know if this is helpful.
