Complete cover than.Look at a production white Leghorn for the answer . They carry barring .
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Complete cover than.Look at a production white Leghorn for the answer . They carry barring .
Complete cover than.
Think of them as gold lace with the genes that deepen the red as RIR have. Then add blue gene= blue laced red.
The 'black'- as in blue-black-splash- of blue laced reds are much darker than gold laceds.
Makes sense, I found a page too that had the original gene sequence for silver laced Wyandotte. Wow, really long! ebeb CoCo db+db+ PgPg MlMl Cha+Cha+ mh+mh+ di+di+ lg+lg+ cb+cb+ i+i+ bl+bl+ Lav+Lav+ C+C+ Mo+Mo+ b+b+ SS Choc+Choc+
I was wondering, say you take a black wyandotte and a white leghorn, will you get a mottled chicken? How do you create a mottled color for a hybrid?
It would help a lot to read a little on basic genetics. Have to ask, what is the reasoning behind all those questions about hybrids?
Mottle is recessive. White leghorns have dominant white. Answer to your question would be white downed chicks with random little dots growing into either solid white or occasional black feather and have rose combs.
As for the hybrid part, the only way you can get mottles in the hybrids is if both parents at least carry mottling.
That's actually listing far more genes than is necessary.. like covering all bases... throughout the whole state lol
That makes more sense. Crazy long gene sequence make face hurt. Didn't know why it had to have all those different colored to make a silver and black bird! Thanks again!
The only truly revealant parts are ebeb CoCo db+db+ PgPg MlMl
It shouldn't even be in any consideration to wonder about the role of lavender(Lav+Lav+), chocolate, mottling(Mo+) in silver lace, for example so at first that sequence seems frighteningly long but honestly most of it can be simply ignored.